It is easier to open a door by holding it from its edge as the displacement from the edge to the hinge of the door is the maximum, which gives a larger moment of force with a small force applied by us, hence, the door opens with lesser effort as compared to the case when we open the door by holding it from anywhere …
Why is it more difficult to open a door as you push closer to the hinges compared to further away from the hinges?
But what it comes down to is that the further from the hinge you apply a force, the less inertia will be on the side of the force opposite the hinge and the faster it will be able to accelerate and the less opposing force the hinge has to provide to cancel the acceleration on its end.
Why is it easier to open a cabinet door when the doorknob is at the end of the door than when it is in the middle of the door?
To make it as easy as possible to open the door, the knobs are placed as far from the hinge as is feasible. This maximizes the lever arm, reducing the amount of force needed to open the door.
Why can’t you open a door by pushing on its hinged side?
Why can’t you open a door by pushing on its hinged side? A force exerted at the hinges produces no torque about them. It’s must easier to carry a weight in your hand when your arm is at your side than it is when your arm is pointing straight out in front of you. Use the concept of torque to explain this effect.
Why can’t you open the door by pushing towards the hinge?
The reason is due to the effect of Torque. The rotational effect increases when the distance increases. It’s easier to open a door if you hold the knob and push closer to the hinges.
How do you calculate the force needed to open a door?
If we have a free ‘door’ (l=1m, M=12Kg, I=4) and we exert force of 120 N on the CM for 1/10 sec, the impulse will be 12 kg m/s but will the acceleration/velocity be: a=J/m=vCM=12/12=1m/s? (that is no sure, see point 1.)
How much force is required to open a door?
Interior doors should require no more than 5 lbs. of force to open. This does not apply to the initial force needed to overcome the weight of a motionless door. Open the door gradually; do not “jerk” it open.
Does a door need a pushing force to open it?
When it comes to rotation, to overcome the moment of inertia you need torque, not regular force. … So pushing on the door from a greater distance from the hinge produces a greater torque on the door, making it easier to open.
Why it is easier to open a door if you pull perpendicularly to the door instead of pulling at an angle?
As distance increases, torque increases and so the rotational effect increases. Hence, it is easier to push open a door by holding the knob than by pushing closer to the hinge. … And larger is the perpendicular distance from the axis of rotation, less is the force needed to move it.
Which push will give the door more rotational motion?
It is much easier to make the revolving door rotate by pushing on the panel far from the central pivot than it is by pushing near the pivot. Why? Answer: Pushing the door far from the pivot produces a larger torque on the door than pushing it near the pivot.
Where should you push on a door to apply the most torque when opening the door?
Pushing on the side closest to the hinges requires considerably more force. Although the work done is the same in both cases (the larger force would be applied over a smaller distance) people generally prefer to apply less force, hence the usual location of the door handle. Figure 1: Opening a door with maximum torque.
Which force is used when we open a door by pulling it with hands?
Opening a door requires our hand to apply force by pushing and pulling which is a contact force. There is some frictional force in the door hinge, against that we apply force. The hinge friction is again a contact force.